t^2=25/4.9

Solution for t^2=25/4.9 equation:

t^2=25/4.9

We move all terms to the left:

t^2-(25/4.9)=0

We add all the numbers together, and all the variables

t^2-(+25/4.9)=0

We get rid of parentheses

t^2-25/4.9=0

We multiply all the terms by the denominator


t^2*4.9-25=0

Wy multiply elements

4.9t^2-25=0

a = 4.9; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·4.9·(-25)
Δ = 490
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{490}=\sqrt{1*490}=\sqrt{1}*\sqrt{490}=1\sqrt{490}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1\sqrt{490}}{2*4.9}=\frac{0-1\sqrt{490}}{9.8}
=-\frac{1\sqrt{490}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1\sqrt{490}}{2*4.9}=\frac{0+1\sqrt{490}}{9.8}
=\frac{1\sqrt{490}}{9.8}
$